Brown, 31, is a former sixth-round pick of the Steelers back in 2010. He was in the third year of his five-year, $72.71 million contract when the Steelers traded him to the Raiders back in March.
The Raiders later signed Brown to a new contract worth $50.125 million and includes $30.125 million guaranteed. However, Oakland made the decision to release Brown before the start of the season and he later signed a one-year deal worth up to $15 million with the Patriots.
Brown lasted just 11 days in New England. The Buccaneers signed him to a contract a few weeks ago.
Brown’s one-year deal with the Buccaneers is worth up to $2.5 million and includes a $750,000 bonus for a Super Bowl win, and three $250,000 bonuses — one for receptions, one for yards and one for TDs.
In 2019, Brown appeared in one game for the Patriots and caught four passes for 56 yards receiving and one touchdown.