According to Ian Rapoport and Mike Garafolo, the Cowboys are expected to sign franchise DE DeMarcus Lawrence to a five-year contract worth more than $100 million.
- According to Todd Archer, Lawrence gets $105 million in total with $65 million guaranteed.
- Albert Breer says that Lawrence gets $31.1 million in year 1, $48 million over two years and $65 million over three years.
- Mike Garafolo reports that Lawrence’s contract will pay him the most money in Year 1 for a defensive player ever.
Reports from earlier in the day mentioned that the two parties were closing in on a deal and it looks like they were able to get the final few details worked out.
Lawrence had said that he wasn’t going to play out another season under the franchise tag and he had been delaying a shoulder surgery until they got a deal done.
In the end, Lawrence will walk away with over $20 million per year as part of a long-term deal, which will put him in the neighborhood of Khalil Mack’s deal with the Bears.
Lawrence, 26, is a former second-round pick by the Cowboys in the 2014 NFL Draft out of Boise State. He finished a four-year rookie contract before the Cowboys used their franchise tag on him last year.
The Cowboys followed that up by franchising Lawrence for the second straight year this offseason.
In 2018, Lawrence appeared in all 16 games for the Cowboys and recorded 64 tackles, 10.5 sacks, an interception, two forced fumbles, a recovery and a pass defense. Pro Football Focus has him rated as the No. 9 overall edge defender out of 103 qualifying players.
We’ll have more regarding the Cowboys and Lawrence as the news is available.
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