The Bills announced Monday they’ve signed TE Lee Smith to a three-year deal.
- According to Ian Rapoport, the deal is worth $9 million total and the first two years of the contract are entirely guaranteed, making Smith a likely roster lock for 2019.
Signed to a three-year contract: TE Lee Smith pic.twitter.com/CUKhQPeuan
— Buffalo Bills PR (@BuffaloBillsPR) May 13, 2019
Smith had visited the Bills following his release from the Raiders last week. He previously played from 2011-2014 in Buffalo.
Smith, 31, is a former fifth-round pick of the Patriots back in 2011. After four years with the Bills, Smith signed a three-year, $9 million contract with the Raiders back in March of 2015.
Smith was set to make a base $3 million base salary for the 2017 season when he agreed to a pay cut in 2017. He returned to the Raiders last year and actually received a bonus from Oakland after the season.
In 2018, Smith appeared in all 16 games for the Raiders and caught 10 passes for 73 yards receiving and three touchdowns.
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