Browns DE Myles Garrett announced via his Twitter account on Wednesday that he’s officially signed his record five-year extension worth $125 million.
— Myles Garrett ⚡️ (@MylesLGarrett) July 15, 2020
That works out to a massive $25 million per year which should make Garrett the NFL’s highest-paid defensive player. The deal will include $100 million in total guarantees, half of which is fully guaranteed at signing, per Rapoport.
Rapoport adds the two sides might not finalize the deal today but they are expected to come to an agreement.
The two sides had recently opened up extension talks as this was the first year Garrett was eligible for a new deal. Garrett has established himself as one of the best young pass rushers in the league despite his suspension late last season.
Back in May, Browns GM Andrew Berry said during an interview with 105.7 The Fan in Baltimore last week that view Garrett as a long-term member of their franchise and want to discuss an extension so this isn’t a big surprise.
“We do see Myles as a long-term member and pillar in our organization,’’ Berry said, via Mary Kay Cabot of the Cleveland Plain Dealer. “Great player, great person. Obviously, he did make a mistake last year that he’s learned from. But our confidence in and faith in Myles has not wavered and we’re looking to seeing what he does this year and certainly for years to come.’’
The Browns officially picked up Garrett’s fifth-year option, which will cost them $15,184,000 for the 2021 season. This figure is guaranteed for injury.
Garrett, 24, is a former first-round pick of the Browns back in 2017. He just finished the third year of his four-year, $30.4 million fully guaranteed contract.
Garrett stands to make a base salary of $4.61 million for the 2020 season.
In 2019, Garrett appeared in 10 games and recorded 29 tackles, 10 sacks, and two forced fumbles.
We’ll have more regarding Garrett and the Browns as the news is available.