Andrew Hawkins announced Wednesday via Uninterrupted that he’s signing with the Patriots.
- Adam Schefter reports that Hawkins receives a one-year contract from New England.
- According to Aaron Wilson, Hawkins declined offers from four other teams to play for the Patriots.
BREAKING: @Hawk announces signing with @Patriots on UNINTERRUPTED. pic.twitter.com/bQpVblBO1W
— UNINTERRUPTED (@uninterrupted) May 24, 2017
The Patriots brought Hawkins in for a visit last week, so he was clearly on their radar as a potential addition. New England is very deep at receiver, which means Hawkins will need to win a roster spot this summer.
Hawkins, 31, originally signed on with the Rams as an undrafted free agent out of Toledo back in 2011. He was later claimed off of waivers by the Bengals and spent three years in Cincinnati before signing a four-year, $13.6 million contract with the Browns in 2014.
Hawkins was in the final year of his contract and set to make a base salary of $1.8 million for the 2017 season when the Browns released him in a move that freed up $3.5 million of available cap space.
In 2016, Hawkins appeared in all 16 games for the Browns and caught 33 passes for 324 yards receiving and three touchdowns. Pro Football Focus has him rated as the No. 89 receiver out of 115 qualifying players.
We had him featured in our Top 50 Available Free Agents list.
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