The Oakland Raiders announced that they’ve signed first-round S Johnathan Abram to a four-year rookie contract.
Autographed the dotted line. 🖊
— Oakland Raiders (@Raiders) June 18, 2019
The Raiders have now signed all but one of their 2019 draft picks including:
|27.||1.||Johnathan Abram||S||Miss. State||Signed|
|230.||7.||Quinton Bell||DE||Prairie View||Signed|
Abram, 22, was the No. 27 overall pick by the Raiders out of Mississippi State. He was the first safety selected in the 2019 NFL Draft.
According to OverTheCap.com, Abram receives a four-year, $11,495,198 rookie contract including a $6,380,144 signing bonus.
Abram transferred to Mississippi State from Georgia following his freshman year. In two years for the Bulldogs, Abram recorded 170 tackles, five sacks, two interceptions, three forced fumbles and 10 passes defensed in 25 games.