The Miami Dolphins officially claimed CB Dee Delaney off of waivers from the Jaguars and placed TE A.J. Derby on injured reserve in a corresponding roster move.
Delaney, 23, wound up signing on with the Jaguars as an undrafted free agent out of Miami this past April. He agreed to a three-year, $1.71 million contract but was waived coming out of the preseason.
The Jaguars later signed Delaney to their practice squad before calling him up in November. He returned to the Jaguars’ practice squad soon after. Jacksonville promoted him to their active roster earlier this week but waived him two days later.
In 2018, Delaney has appeared in one game for the Jaguars but has yet to record a statistic.
Derby, 26, is a former sixth-round pick of the Patriots back in 2015. He’s currently in the third year of his four-year, $2,392,052 rookie contract and set to make a base salary of $615,000 for the 2017 season.
Derby was waived with an injury designation during the 2015 preseason and later reverted to the Patriots’ injured reserve list. New England wound up trading him to the Broncos for a 2017 fifth-round pick after appearing in four games for the Patriots.
Denver waived Debry with an injury designation a few weeks ago and he later reverted to injured reserve before being cut loose last week. Miami quickly claimed him off waivers from the Broncos.
So far this season, Derby has appeared in nine games and recorded 19 receptions for 224 yards receiving, two touchdowns, and lost one fumble.
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