Seahawks Open To Making Jamal Adams Highest-Paid Safety In NFL

According to Ian Rapoport, the Seahawks are open to making Jamal Adams the league’s highest-paid safety. However, the organization would like to keep his potential extension below LB Bobby Wagner‘s $18 million per year. 

Jamal Adams

Rapoport adds that this would likey mean Seattle is eying a deal in the $17 million annual range. 

Adams is entering the final year of his deal and is seeking a contract extension that makes him the NFL’s highest-paid safety, so this doesn’t come as a big surprise. 

Adams, 25, is a former first-round pick of the Jets out of LSU back in 2017. He just finished the fourth year of his four-year rookie contract worth $22,256,084, which includes a signing bonus of $14,326,244.

The Jets exercised Adams’ fifth-year option before ultimately trading him to the Seahawks for a package including two first-round picks. The option will cost the Seahawks $9.86 million for the 2021 season. 

In 2020, Adams appeared in 12 games for the Seahawks and recorded 83 total tackles, 11 tackles for loss, 9.5 sacks, one forced fumble, no interceptions, and three pass defenses. Pro Football Focus had him rated as the No. 53 safety out of 94 qualifying players. 

We’ll have more on Adams as the news is available. 

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